Thank you very much for the reply. I am bit confused, I would like to recap what you said and please tell me if I am wrong.
# Speakers = 4, 2 per side.
HF = 120w @ 8ohms program power
LF = 500w @ 8ohms program power
Using your calculation.
Hf = 60w @ 4 ohms Continuous power (120/2)
LF = 250w @ 4ohms Continuous power (500/2)
So, Minimum power = 2 x Continuous power
HF = 120w @ 4ohms & LF = 500w @ 4 ohms (60 * 2x & 250 * 2x)
For 2 speakers, HF = 240w & LF = 1000w
My confusion is that should not LF = 1000w for 2 speakers? If so, then Can I use i-tech400 for LF.
I am also confused about the impedance. I am assuming that when you divide the program power by 2, the impedance also devided by 2 to get 4
(speaksers are 8ohms).
So if the impedance is 4 for one speakers, then should not it be 2ohms when I add the 2nd speakers.
Thank you for the help and please excuse my ignorance.